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30n^2-128n+128=0
a = 30; b = -128; c = +128;
Δ = b2-4ac
Δ = -1282-4·30·128
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-32}{2*30}=\frac{96}{60} =1+3/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+32}{2*30}=\frac{160}{60} =2+2/3 $
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